Radius of big drop =R Number of small drops, n=64 Let radius of small drop =r In the process of breaking the drop, the volume of liquid drops remains constant. Vi=Vf ⇒
4
3
πR3=n(
4
3
πr3) R3=64r3⇒R=4r ⇒r=
R
4
Now, work done in breaking a big drop in 64 small drops. W= final energy − initial energy W=T(n4πr2)−T(4πR2)=4πT[64(