Applying KVL from A to B, VA−10I−20I1=VB 10−10I−20I1=6 4=10[I+2I1] Applying KVL from A to C, VA−10I−30I+30I1=VC 10=40I+30I1+5 5=40I−30I1 1=8I−6I1 I1=
8I−1
6
... (ii) Putting the value of I1 in Eq. (i), 4=10[I+
2
6
(8I−1)] 4=10[I+
8
3
I−
1
3
]⇒4=10[
11I
3
−
1
3
] 1.2=11I−1 11I=2.2⇒I=
1
5
Let current in 10Ω is I, Current in 20Ω is I1 and Current in 30Ω is I−I1 I1=
