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UPSC 2014 CDS I Math Paper
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© examsnet.com
Question : 44
Total: 100
The dimensions of a field are 15m by 12m. A pit 8m long, 2.5m wide and 2m deep is dug in one corner of the field and the earth removed is evenly spread over the remaining area of the field. The level of the field is raised by
[2014 CDS-I]
15 cm
20 cm
25 cm
200
9
cm
Validate
Solution:
Volume of earth dug out
=
8
×
2.5
×
2
=
40
m
3
Area of the remaining field = Area of the field - Area of the pit
=
15
×
12
−
8
×
2.5
=
160
m
2
Therefore, rise in the level of the field
=
Volume of earth dug out
Area of the remaining field
=
40
160
=
1
4
m
=
1
4
×
100
c
m
=
m
© examsnet.com
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