Let the length, breadth and height of the cuboid be l, b and h, respectively. ∴l2+b2=132=169....(1) b2+h2=(√281)2=281....(2) h2+I2=202=400...(3) Adding eq (1), (2) and (3), we have 2(l2+b2+h2)=850 ⇒l2+b2+h2=425....(4) From (1) and (4), we have h2=425−169=256 ⇒h=16units Similarly, l = 12 units andb = 5 units Therefore, total surface area of thecuboid = 2(lb + bh + hl) =2(12×5+5×16+16×12) = 664 square units