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UPSC 2016 CDS II Math Paper
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© examsnet.com
Question : 55
Total: 100
A drinking glass of height 24 cm is in the shape of frustum of a cone and diameters of its bottom and top circular ends are 4 cm and 18 cm respectively. If we take capacity of the glass as
π
x
c
m
3
, then what is the value of ?
[2016 CDS-II]
824
1236
1628
2472
Validate
Solution:
Let
r
1
and
r
2
be the radii of the bottom and top circular ends of the frustum of the cone, respectively.
Here,
r
1
=
2
cm and
r
2
=
9
cm
Height of the frustum of the cone = h = 24 cm
Capacity of the glass
=
π
x
c
m
3
∴
1
3
π
h
(
r
1
2
+
r
1
r
2
+
r
2
2
)
=
π
x
⇒
1
3
×
24
×
(
4
+
18
+
81
)
=
x
⇒
x
=
824
© examsnet.com
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