When a = b = c. √a2+b2=√2a2=√2a √c2+a2=√2a2=√2a b+c=a+a=2a Now,(√2a)2+(√2a)2 =2a2+2a2 =4a2=(2a)2 For a = b = c, √a2+b2,√c2+a2 and (b+c) form the sides of a right triangle with hypotenuse (b + c). ∴ Area of the triangle =
1
2
×√2a×√2a =a(
b+c
2
) =
a(b+c)
2
Trick :Take a=3,b=4,c=4, Then √a2+b2=5,√c2+a2=5 b+c=8 ∴s=