Two consecutive integers can be written in the form 2m and 2m + 1. Here, 2m is an even integer and (2m + 1) is an odd integer. So, of the two consecutive integers, one is even. Hence, statement 1 is correct Remember: The product of two consecutive integers is always divisible by 2. (2m+1)2=4m2+4m+1 =4m(m+1)+1 =4×2n+1=8n+1 Thus, the square of an odd integer is of the form 8n+1. Hence, statement 2 is correct.