Let the three consecutive natural numbers be (x – 1), x and (x + 1). Then, (x−1)2+x2+(x+1)2=110
⇒x2−2x+1+x2+x2+2x+1=110
⇒3x2=108⇒x2=36⇒x=6 Since natural numbers are positive integers, therefore, we cannot consider x = –6. Other numbers are (x – 1), i.e., 5 and (x + 1), i.e., 7. Sum of cubes of numbers=53+63+73=684