Object distance, u=−40cm Focal length, f=25cm Let v be the image distance. From lens formula,
1
f
=
1
v
−
1
u
⇒
1
v
=
1
f
+
1
u
=
1
25
+
1
(−40)
⇒
1
v
=
1
25
−
1
40
=
8−5
200
=
3
200
⇒v=
200
3
=66.7cm Now, magnification produced by lens, m=
v
u
=
66.7
(−40)
=−1.66 Since, the magnification is negative, so the image formed will be real and inverted. Also, the magnitude of magnification is greater than unity, so the image will be magnified.