In right angled triangle PCQ PQ2=CQ2+PC2 ………..(1) In Right angled triangle ABC AB2=CB2+AC2 ………(2) Adding (1) and (2) ⇒AB2+PQ2=CB2+AC2+CQ2+PC2 ⇒AB2+PQ2=(AC2+CQ2)+(CB2+PC2) AB2+PQ2=AQ2+BP2 Hence, statement (1) is correct. Consider statement (2) Now, AB = 2PQ is true only if P and Q are midpoints of AC and BC respectively. But it is not mentioned in question that P and Q are midpoints of AC and BC respectively. Hence, statement (2) is not correct.