Let the LCM and HCF of two numbers be x and y respectively. Now, according to the question, x+y=536 x−y=296 Adding Eq. (i) and Eq. (ii), we get 2x=832⇒x=416 From Eq. (i), 416+y=536 ⇒y=536−416=120 LCM=x=416 and HCF=y=120 We know, Product of LCM and HCF= Product of two numbers. Let the other number be P.
∴416×120=104×P[∵ one of the numbers is 104] ⇒P=