Now, in the △ACD&△AOB ∠A= common angle, &∠O=∠C=90∘ ⇒△ACD∼△AOB ⇒OB∕CD=30∕h=R∕r According to the question, The volume of a small cone ∕ Volume of a cone =1∕27 ⇒
1
3
πr2h
1
3
πR2×30
=
1
27
⇒(
r
R
)2×
h
30
=
1
27
.⇒(
h
30
)2=
1
27
[From eq (1),r∕R=h∕30] ⇒27h3=27000 ⇒h3=1000 ⇒h=10cm Height from the base ⇒(30−10)cm=20cm