Area of a circle =πx2 Where x= radius of the circle
Let the radii of two circles be R and r According to the question: R+r=13cm⋯−(i) Also, πR2+πr2=89π ⇒R2+r2=89 We know that (R+r)2=R2+r2+2R ⇒169=89+2Rr ⇒Rr=40 From (i) and (ii), we get ⇒R(13−R)=40 ⇒R2−13R+40=0 ⇒(R−8)(R−5)=0 ⇒R=8,5;r=5,8 Difference between their radii = 3 cm