Time =( Distance covered )∕( Speed ) When a train passes a station, distance covered = (Length of train + Length of station). Calculation: Case 1: Through station of length x (L+x)∕v=t... (i) Case 2: Through station of length y (L+y)∕v=2t... (ii) From (i): v=(L+x)∕t From (ii): v=(L+y)∕(2t) Equating both values of v : (L+x)∕t=(L+y)∕(2t) 2(L+x)=(L+y) 2L+2x=L+y L=y−2x... (iii) Now, time to pass station of length (x+y) : Required time =(L+(x+y))∕v Using (i): v=(L+x)∕t So, Required time =(L+x+y)∕((L+x)∕t) =[(L+x+y)×t]∕(L+x) Substitute L=y−2x : =[(y−2x+x+y)×t]∕(y−2x+x) =[(2y−x)×t]∕(y−x)
