The chords AB and CD intersect at a point P.
∴ PA × PB = PC × PD
⇒P'A' × P'B' = C'Q' × D'Q'.......(1)
⇒=Since the corresponding sides of the triangles A'P'B' and C'Q'D' are not proportional, so triangles A'P'B' and C'Q'D' are not similar.
Now,A'P' ≠ C'Q',P'B' ≠ Q'D' and A'B' ≠ C'D'.So, triangles A'P'B' and C'Q'D'are not congruent.
Also, the perimeters of the triangles A'P'B' and C'Q'D' are not same.
From (1) we have
Therefore, area of ΔA'P'B' = Area of ΔC'Q'D'
Hence, statements 1, 2 and 4 are not correct.