Let ABC is equilateral triangle with A(0,0) and B(3,√3) and C to be known.
∴AB=√(3−0)2+(√3−0)2=√9+3=√12
Take option (a) i.e C(0,2√3) CA=√02+(2√3)2=√12 CB=√(3)2+(√3)2=√12 Take option (b) i.e.C(3,−√3) CA=√32+(√3)2=√12 CB=√(0)2+(2√3)2=√12 ∴ Both option (a) and (b) are correct.