Considering the first equation, we get a(x−8)(x−2)=0 x2−10x+16=0...........(i) Since,the constant term in the above equation is wrong,the original equation will be of the form x2−10x+c=0...(ii) Considering the second equation, we get (x+9)(x+1)=0 x2+10x+9=0...(iii) Since, only the coefficient of first degree term in the above equation is wrong, the constant term is 9. Therefore from, (ii) and (iii), we get the original equation as x2−10x+9=0