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UPSC NDA II 2015 Mathematics Solved Paper

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For the next two(2) items that follow :

Consider the function

f(x)=\begin{cases} -2\sin x, & \text{if } x \le -\pi/2 \\ A\sin x + B, & \text{if } -\pi/2 < x < \pi/2 \\ \cos x, & \text{if } x \ge \pi/2 \end{cases}

Which is continuous everywhere

[NDA II 2015]

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Question : 100 of 120

Marks: +1, -0

The value of B is

1
0
$-1$
$-2$

Solution:

Put the value of A in eq. (2) we get:

\Rightarrow B=1

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