Here, we have to find the equation of the hyperbola whose foci are (±√29,0) and the transverse axis is of length 10. By comparing the foci (±√29,0) with (± ae, 0) ⇒ae=√29 ∵ The length of transverse axis is 10 ⇒2a=10⇒a=5 ⇒5e=√29 ⇒e2=29∕25 As we know that, e=
√a2+b2
a
⇒a2e2=a2+b2 ⇒b2=29−25=4 So, the equation of the hyperbola is