Let the three numbers in A.P. be a – d, a, and a + d. Given: the sum of three numbers in A.P. is 24 ⇒ (a – d) + a + (a + d) = 24 ⇒ 3a = 24 ⇒ a = 8 Also, given: the product of three numbers in A.P. is 440. ⇒ (a – d) (a) (a + d) = 440 Put a = 8 ⇒ (8 – d) (8) (8 + d) = 440 ⇒ (8 – d) (8 + d) = 55 ⇒64–d2=55 ⇒d2=9 ⇒d=±3 Therefore, when d = 3, the numbers are 5, 8, and 11 and when d = –3, the numbers are 11, 8, and 5. So, the three numbers are 5, 8, and 11.