Here, we have to find the equation of the hyperbola whose vertices are (0, ± 3) and the eccentricity is 4/3 By comparing the vertices (0, ± 3) with (0, ± a) we get ⇒ a = 3 As we know that, e=
√a2+b2
a
⇒a2e2=a2+b2 ⇒16=9+b2 ⇒b2=7 so, the equation of the hyperbola is