=e2xdx Integrating both sides, we get ⇒∫e−3ydy=∫e2xdx ⇒
e−3y
−3
=
e2x
2
+c ⇒2e−3y=−3e2x−6c .......(1) By using y = 0 when x = 0, we get ⇒ 2 = -3 – 6c ∴ c = -5/6 Put the value of c in equation 1st ⇒2e−3y=−3e2x−6(−5∕6) ⇒2e−3y=−3e2x+5 ⇒2e−3y+3e2x=5