Here, 2x + y = 6 ... (1) And, 3y = 8 + 4x ⇒4x - 3y = -8 .... (2) Multiply (1) and subtract from (2), we get (4x + 2y = 12) - (4x - 3y = -8 ) ⇒ 5y = 20 ⇒ y = 4 Putting y = 4 in (1), we get x = 1 Now let's check which equation in the option satisfy the values of x and y 1. x + y = 1 + 4 = 5 Hence, option (1) is correct.