Given circles are x2+y2−4x−2y=0 and x2+y2−6y+4=0 Centre of 1st circle =C1=(2,1) Radius of 1st circle =r1=√(22+12)=√5 Centre of 2nd circle =C2=(0,3) Radius of 1st circle =r2=√(02+32−4)=√5 Now, C1C2=√((0−2)2+(3−1)2)=√(22+22)=√8=2√2 And r1+r2=√5+√5=2√5 Here r1+r2>C1C2 Thus, two circles intersect each other.