Given equation are 2x2+3x+5λ=0 and x2+2x+3λ=0 To Find: Value of λ 2x2+3x+5λ=0 .... (1) x2+2x+3λ=0 .... (2) Subtracting [2 × equation (2) - equation (1)], we get ⇒2x2+4x+6λ−(2x2+3x+5λ)=0−0 ⇒ x + λ = 0 ∴ x = -λ Put the value of x in equation (1), we get ⇒2(−λ)2+3(−λ)+5λ=0 ⇒2λ2+2λ=0 ⇒ 2λ (λ + 1) = 0 ∴ λ = 0 and -1