Here, cosθ1+cosθ2+cosθ3+cosθ4+cosθ5=5 Since, the maximum value of cos θ = 1 We have five terms in LHS of the given equation. Every term should be = 1 cosθ1=cosθ2=cosθ3=cosθ4=cosθ5=1 ∴θ1=θ2=θ3=θ4=θ5=0° Now, sinθ1+sinθ2+sinθ3 =3×(sin0°) =0 Hence, option (1) is correct.