Here, radius = 6 and centre at (3, 5) ∴Equation of circle = (x−3)2+(y−5)2=62⇒(x−3)2+(y−5)2=36 Now check the points, 1. (-2, -1): ⇒(−2−3)2+(−1−5)2=25+36>36 So, this point lies outside of circle. 2.(0, 1): ⇒(0−3)2+(1−5)2=9+16<36 So, point (0,1) lies inside the circle Hence, option (2) is correct.