The line has the slope -1 and passes through (2, 4) ∴ Equation of the perpendicular line is (y−y1)=m(x−x1) ⇒y−4=−1(x−2) ⇒y=−x+6 .......(i) Slope (m1)=−1 and c1=6 Now for the slope of perpendicular line (m2) m1×m2=−1 ⇒−1×m2=−1 ⇒m2=1 Perpendicular line has the slope 1 and passes through (−1,3) ∴ Equation of the perpendicular line is (y−y1)=m(x−x1) ⇒y−3=1(x−(−1)) ⇒y=x+4 .......(ii) Adding (i) and (ii) ⇒ 2y = 10 ⇒ y = 5 Putting y in equation (ii) 5 = x + 4 ⇒ x = 1 ∴ The point of intersection is (1, 5)