Given, Applied variable horizontal force F=8|sin(4πt)|N Mass of block (m)=2kg Friction coefficient between block and ground µ=0.5 and g=10m∕s2 We know that maximum possible friction force, Ffriction max =µmg =0.5×2×10 =10N .......(i) Maximum applied force (Fapplied max )=8×1 =8N ........(ii) [∵ maximum value of sinθ is 1] From equation (i) and (ii), we get ffriction max>fapplied max So, the block will remain stationary.