Given, t=500nm µ=1.5 (refractive index of oil) r=0° (as white light incident normally) n=1.24 (refractive index of liquid) Since, 2µt‌cos‌r=(n+1).λ ∴λ=
2×1.5×cos‌0°×500
2.24
nm =669.64nm which is close to 650nm , hence correct option is (d).