ΔG° of a reaction is given by the expression. ΔG°=−2.303RTlogK ......(i) Given, K=102 T=27°C or 300K on putting the values in Eq (i) ΔG°=−2303×8.314JK−1mol−1×300×log102 ΔG°=−1148.28Jmol−1 or −11.48kJmol−1 Now, as the reaction is at equilibrium, hence ΔG=0.