The work done during the process from D to C= area of DCQP, which is in shown figure below
⇒ Area DCQP=2p×(2V−V)=2pV Work done during B to A=− area ABQP Where, negative sign is due to compression along BA. ⇒ area ABQP=−p×(2V−V)=−pV Hence, the work done in the complete cycle. =2pV−pV=pV ∴ Correct option is (a).