Given, R0=100Ω,T1=0°C,T2=60°C and temperature coefficient of resistance, α=0.0045°C−1 As, resistance of a metal at the temperature T is given by Rt=R0[1+α(T2−T1)] ⇒Rt=100[1+0.0045(60°−0°)] ⇒Rt=100[1+0.27]⇒Rt=127Ω So, the resistance of platinum wire at 60°C is 127Ω.