Let dimension of Energy [E] = [G]a [V]b [T]c Dimension of ‘E’ when fundamental unit M(mass), L (length) and T(time) is given by [ML2T–2] So, [ML2T–2] = [G]a[V]b[T]c On putting dimension of G and V in term of fundamental unit M, L and T [ML2T–2] = [M–1L3T–2]a[LT–1]b[T]c [ML2T–2] = [M]−a[L]3a+b[T]–2a−b+c Compare the power of [M], [L] and [T] –a =1 …(i) 3a + b = 2 …(ii) –2a -b + c = – 2 …(iii) a = -1, b = 5, c = 1 So, dimension of Energy = [G]–1[V]5[T]1 = [G–1V5T]