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UPSEE Solved Model Paper 1
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© examsnet.com
Question : 48
Total: 150
A particle of mass ‘m’ moving with an initial speed
v
0
collides elastically with another particle of mass ‘2m’ which is in rest initially. After collision first particle moves with speed
v
0
in perpendicular direction to its initial direction of motion. Speed of other particle will be (Consider all Motion in a two dimensional plane)
v
0
v
0
∕
2
√
2
v
0
v
0
∕
√
2
Validate
Solution:
By conservation of linear momentum in x direction
m
v
o
=
2
m
v
x
𝑣
𝑥
=
𝑣
0
2
conservation of linear momentum in y direction 0 =
m
v
o
+
2
m
v
y
𝑣
𝑦
=
−
v
0
2
Speed of other particle
v =
√
v
x
+
v
y
2
=
√
(
v
0
2
)
2
+
(
−
v
0
2
)
2
=
v
0
√
2
© examsnet.com
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