As given m = 10 kg FBD for upper block (10 kg)
As maximum static friction =
µsN = 0.5 × 10 × g = 50N
as 60 N is greater than force of static friciton (maximum)
So, block will slip over the lower one and hence force of kinetic friction
fk has to be considered in that case and
fk =
bk N = 0.3 × 10 × 10 = 30 N
u = ∞
⇒ v = f (from formula)
Also,
h1 = - fθ
For plane mirror object distance is d - f.
⇒ x = (d - f), y = - fθ