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UPSEE Solved Model Paper 4
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© examsnet.com
Question : 50
Total: 150
A mass
m
1
with initial speed
v
0
in the positive x direction collides with a mass
m
2
=
2
m
1
which is initially at rest at the origin, as shown in figure. After the collision
m
1
moves off with speed
v
1
=
v
0
∕
2
in the negative y- direction, and
m
2
moves off with speed
v
2
at angle θ. Find the velocity (magnitude and direction) of the centre of mass after the collision :
v
0
∕
3
v
0
∕
2
v
0
∕
5
v
0
∕
6
Validate
Solution:
Since there is no external force acting on the 2 mass system, the momentum of the system and the celocity of the centre of mass remains constant.
Therefore,
V
cm
is the same before and after the collision,
i.e.,
V
cm
,
x
=
m
1
v
1
+
m
2
v
2
m
1
+
m
2
as
m
2
=
2
1
and
V
cm
,
y
= 0
V
cm
,
x
=
m
1
v
0
+
2
m
1
×
0
m
1
+
2
m
1
=
v
0
3
© examsnet.com
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