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UPSEE Solved Model Paper 6
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© examsnet.com
Question : 8
Total: 150
For a projectile, the ratio of maximum height reached to the square of flight time is (g = 10
m
s
−
2
)
5 : 4
5 : 2
5 : 1
10 : 1
Validate
Solution:
for projectile motion the maximum height (H) and time of flight (T) are :
H =
u
2
s
i
n
2
θ
2
g
, T =
2
u
s
i
n
θ
g
⇒
H
T
2
=
u
2
s
i
n
2
θ
2
g
g
2
4
u
2
s
i
n
2
θ
=
g
8
=
10
8
=
5
4
© examsnet.com
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