After collision the bullet and block move together and comes to rest after covering a distance of 40 m.
By conservation of momentum m1u1+m2u2=m1v1+m2v2 ⇒ 0.02 × 250 + 0.23 × 0 = 0.02v + 0.23v 5 + 0 = v (0.25) or v = 20 ms−1 Now, by conservation of energy or