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VITEEE 2011 Solved Paper
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© examsnet.com
Question : 72
Total: 120
The rate constant of a reaction at temperature 200 K is 10 times less than the rate constant at 400 K. What is the activation energy of the reaction?
1842.4R
460.6R
230.3 R
921.2 R
Validate
Solution:
At
T
1
= 200 K,
if
k
1
= k then
at
T
2
= 400 K,
k
2
= 10 k
log
10
k
k
=
E
a
2.303
R
(
400
−
200
400
×
200
)
E
a
= 921.2 R
© examsnet.com
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