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VITEEE 2011 Solved Paper
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© examsnet.com
Question : 73
Total: 120
A vessel at 1000 K contains
C
O
2
with a pressure of 0.5 atm. Some of the
C
O
2
is converted into CO on the addition of graphite. The value of K if the total pressure at equilibrium is 0.8 atm, is
1.8 atm
3 atm
0.3 atm
0.18 atm
Validate
Solution:
Initial Equilibrium =
C
O
2
+
c
0.5
0.5
−
x
⇌
2
C
O
0
2
x
Total pressure at Equilibrium
=
0.8
atm
Now
(
0.5
−
x
)
+
2
x
=
0.8
atm
∴
x
=
0.8
−
0.5
=
0.3
Pressure of
C
O
2
at equilibrium
=
0.5
−
0.3
=
0.2
atm
Pressure of
C
O
at equilibrium
=
2
×
0.3
=
0.6
atm
∴
K
=
(
p
c
o
)
2
p
c
o
2
=
(
0.6
)
2
0.2
=
0.36
0.2
=
1.8
atm
© examsnet.com
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