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VITEEE 2014 Paper

Section: Chemistry

Question : 67 of 120

Marks: +1, -0

Which of the following has the maximum number of unpaired d-electrons?

Solution:

\mathrm{Fe}^{2+}

has the maximum number of unpaired d-electrons.

\mathrm{Zn}(30)=[\mathrm{Ar}]\,3d^{10},4s^{2}

\mathrm{Zn}^{2+}=[\mathrm{Ar}]\,3d^{10}:

No unpaired electron

\mathrm{Fe}(26)=[\mathrm{Ar}]\,3d^{6},4s^{2}

\mathrm{Fe}^{2+}=[\mathrm{Ar}]\,3d^{6}:

Four unpaired electrons.

\mathrm{Ni}(28)=[\mathrm{Ar}]\,3d^{8},4s^{2}

\mathrm{Ni}^{3+}=[\mathrm{Ar}]\,3d^{7}:

Three unpaired electrons.

\mathrm{Cu}(29)=[\mathrm{Ar}]\,3d^{10},4s^{1}

\mathrm{Cu}^{+}=[\mathrm{Ar}]\,3d^{10}:

No unpaired electrons.

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