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VITEEE 2015 Solved Paper
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© examsnet.com
Question : 11
Total: 120
Equal charges q each are placed at the vertices of an equilateral triangle of side r. The magnitude of electric field intensity at any vertex is
2
q
4
π
ε
0
r
2
q
4
π
ε
0
r
2
√
3
q
4
π
ε
0
r
2
√
2
q
4
π
ε
0
r
2
Validate
Solution:
Due to charge at A and B magnitude of intensity of electric field at point C
E
1
=
E
2
=
1
4
π
ε
0
q
r
2
Net intensity at point C is
E
R
=
√
E
1
2
+
E
2
2
+
2
E
1
E
2
c
o
s
60
°
=
√
E
1
2
+
E
2
2
+
2
E
1
2
×
1
2
=
√
3
E
1
=
√
3
q
4
π
ε
0
r
2
© examsnet.com
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