VITEEE 2015 Solved Paper

Let initially, pressure of C6H6 (g) is p1 mm and for H2 (g) is p2 mm
∴ p1+p2 = 60 mm ... (i)
After the reaction pressure of C6H6 (g) = 0 (as all C6H6 has reacted)
H2(g) = p2−3p1
So, total pressure = p2−3p1+p1 = 30 mm
p2−2p1 = 30 mm ... (ii)
On solving equation (i) and (ii)
p1 = 10 mm , p2 = 50 mm
Fraction of C6H6 by volume = moles fraction fraction of pressure =

10

60

=

1

6