Let the normal 't1’ cuts the parabola again at the point ‘t2' the equation of the normal at (at12,2at1) is y + t1x = 2at1+at13 Since it passes through the point 't2' i.e. (at22,2at2) ∴ 2at2+at1t22 = 2at1+at13 ⇒ 2a(t1−t2) + at1(t12−t22) = ⇒ 2 + t1(t1+t2) = 0 (Since t1−t2 ≠0) ⇒ 2 + t12+t1t2 = 0 ⇒ t1t2 = - (t12+2) ⇒ t2 = - (t1+