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VITEEE 2018 Solved Paper
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© examsnet.com
Question : 11
Total: 125
Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I =
I
0
sin ωt, where
I
0
= 10 A and ω = 100 π radian/sec. The maximum value of e.m.f. in the second coil is
2 π
5 π
π
4 π
Validate
Solution:
e =
M
d
i
d
t
= 0.005 ×
d
d
t
(
I
0
s
i
n
ω
t
)
= 0.005 ×
I
0
ω
c
o
s
ω
t
∴
e
max
= 0.005 × 10 × 100π = 5π [Since cos ωt = 1]
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