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VITEEE 2019 Solved Paper
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© examsnet.com
Question : 17
Total: 125
A mass of 0.5 kg moving with a speed of 1.5 m/s on a horizontal smooth surface, collides with a nearly weightless spring of force constant k = 50 N/m. The maximum compression of the spring would be
0.5 m
0.12m
0.15m
1.5m
Validate
Solution:
Apply law of conservation of energy,
1
2
m
v
2
=
1
2
k
x
2
⇒
m
v
2
=
k
x
2
or
0.5
×
(
1.5
)
2
=
50
×
x
2
∴
x
=
0.15
m
© examsnet.com
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