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VITEEE 2019 Solved Paper
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© examsnet.com
Question : 33
Total: 125
The surface of a metal is illuminated with the light of 400 nm. The kinetic energy of the ejected photoelectrons was found to be 1.68 eV. The work function of the metal is (he = 1240 eV.nm)
3.09 eV
1.42 eV
1.51 eV
1.68 eV
Validate
Solution:
Energy of incident light,
E
=
12400
λ
(
Å
)
E
=
1240
400
=
3.1
e
V
∵
E
=
W
0
+
K
max
⇒
3.1
=
W
0
+
1.68
⇒
W
0
=
1.42
e
V
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