In given, Series R−L−C circuit Resistance R=100Ω Inductance of Inductor, L=20mH=20×10−3H Resonance frequency f=
1250
π
Hz Source voltage VDC=25V According to resonant frequency. ω0=2πf0=
1
√LC
or (2πf0)2=
1
LC
or 4π2
1250×1250
π×π
=
1
LC
or C=
1000
1250×1250×4×20
("By substituting L=20×10−3) or C=8×10−6F We know that, Charge Qs=CV QS=8×10−6×25=0.2mC So, the amount of charge stored in each plate of capacitor is 0.2mC.