To determine the number of moles of ions produced by complete dissociation of one mole of Mohr's salt in water, we first need to understand its chemical composition and how it dissociates.
Mohr's salt is a double salt with the chemical formula
FeSO4​⋅(NH4​)2​SO4​⋅6H2​O. When it dissociates completely in water, it produces ions from each of its constituent compounds.
The dissociation can be represented as follows:
FeSO4​⋅(NH4​)2​SO4​⋅6H2​O→Fe2++SO42−​+2NH4+​+SO42−​+6H2​O Let's break this down step by step:
1. One mole of
FeSO4​ produces:
1 mole of
Fe2+1 mole of
SO42−​2. One mole of
(NH4​)2​SO4​ produces:
2 moles of
NH4+​1 mole of
SO42−​Summing up all the ions produced, we get:
1 mole of
Fe2+2 moles of
SO42−​2 moles of
NH4+​ Therefore total number of moles of ions produced by complete dissociation of one mole of Mohr's salt are:
1+2+2=5 moles of ions
Thus, the correct answer is:
Option C: 5